SOLVED: Question: Find the derivative of the inverse trig function. y=x sin ^-1√(x) Answer choices: A y^'=x sin ^-1√(x)+(1)/(√(1-x)) B y^'=sin ^-1√(x)+( x)/(√(1-x)) C y^'=x sin ^-1√(x)+(1)/(2 √(x(1-x))) D y^'=(√(x))/(2 √(1-x))+sin ^-1√(x)
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Ex 12.2, 4 - Find derivative of f(x) = 1/x^2 from first principle
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